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JavaScript获取Django模板中指定键值的数据，使…

2019-08-13 08:31:32来源：博客园阅读 ()

Django中利用js来操作数据的常规操作一般为点(.)操作符来获取字典或列表的数据，一般如{{data.0}}，{{data.arg}}

但有时如果数据是嵌套类型的数据时，直接获取某个值就变得困难了，比如下面的格式要获取

correct中qxl的值

startArgsSet={"correct":{"qxl":0,"kkx":0},"reliable":{"qxl":0,"kkx":0},"security":{"qxl":0,"kkx":0},"understand":{"qxl":0,"kkx":0},"entropy":{"qxl":0,"kkx":0},
"mature":{"qxl":0,"kkx":0},"active":{"qxl":0,"kkx":0},"service":{"qxl":0,"kkx":0},"file":{"qxl":0,"kkx":0},
"tech":{"qxl":0,"kkx":0},"property":{"qxl":0,"kkx":0},"organize":{"qxl":0,"kkx":0},"develop":{"qxl":0,"kkx":0},
"source":{"qxl":0,"kkx":0},"update":{"qxl":0,"kkx":0},"fix":{"qxl":0,"kkx":0},
"quality":{"qxl":0,"kkx":0},"meanNum":{"qxl":0,"kkx":0},"variance":{"qxl":0,"kkx":0}
}

这时候如果改变数据格式为列表中的无嵌套字典格式比较麻烦，可以自定义过滤器来获取数据，

from django.template.defaulttags import register

@register.filter
def getArgQxlValue(dictionary,arg):
    return dictionary[arg]['qxl']
    
@register.filter
def getArgKkxValue(dictionary,arg):
    return dictionary[arg]['kkx']
    
@register.filter
def getArgName(dictionary,arg):
    return dictionary[arg]['name']

在模板中就可以以这样写

<!-- the second important page of the project-->
{% load staticfiles %}

<!DOCTYPE html>
<html>
<head>
    <meta charset="utf-8">
    <title>超标信息</title>

     <script src="{% static 'js/a-mynewjs.js' %}"></script>

</head>

<body>

  {{ guestSetArgs|safe }}<br><br><br>
  
  {{ warningdata|safe }}<br><br>
  
  <script>
  {% for i in guestSetArgs %}
    {% for j in warningdata %} 
       if("{{i}}"=="{{j}}")
       {
           if(Number({{warningdata|getArgQxlValue:j}})>Number({{guestSetArgs|getArgQxlValue:i}}))
           var setArgStr="{{warningdata|getArgName:i}}&nbsp;超出阀值&nbsp;&nbsp;阀值：{{guestSetArgs|getArgQxlValue:j}}&nbsp;&nbsp;检测值：{{warningdata|getArgQxlValue:j}}<br>"
           document.write(setArgStr);
       }
       
    {% endfor %} 
  {% endfor %} 
  
    </script>
</body>
</html>