C++ 实现矩阵相乘
2018-07-20 来源:open-open
#include <iostream>
using namespace std;
void MatrixMultiplication(double *m1,double *m2,double *m3,int m,int n,int k)
{
for(int i=0;i<m;i++)
{
for(int j=0;j<k;j++)
{
double sum = 0.0;
for(int jj=0;jj<n;jj++)
{
sum += *(m1+i*n+jj)*(*(m2+jj*k+j));
}
*(m3+i*k+j) = sum;
}
}
}
int main(int argc, char* argv[])
{
int m = 1 , n = 3 , k = 3;
double *m1,*m2,*m3;
m1 = new double[m*n];
m2 = new double[n*k];
m3 = new double[m*k];
//[50 50 1]
*(m1+n*0+0) = 50;
*(m1+n*0+1) = 50;
*(m1+n*0+2) = 1;
//[1 0 0]
//[0 1 0]
//[200, 200,1]
*(m2+k*0+0) = 1;
*(m2+k*0+1) = 0;
*(m2+k*0+2) = 0;
*(m2+k*1+0) = 0;
*(m2+k*1+1) = 1;
*(m2+k*1+2) = 0;
*(m2+k*2+0) = 200;
*(m2+k*2+1) = 200;
*(m2+k*2+2) = 1;
MatrixMultiplication(m1,m2,m3,m,n,k);
cout<<"["<<*(m3+k*0+0)<<" ";
cout<<*(m3+k*0+1)<<" ";
cout<<*(m3+k*0+2)<<"]"<<endl;
delete[] m1;
delete[] m2;
delete[] m3;
return 0;
}
标签:
版权申明:本站文章部分自网络,如有侵权,请联系:west999com@outlook.com
特别注意:本站所有转载文章言论不代表本站观点!
本站所提供的图片等素材,版权归原作者所有,如需使用,请与原作者联系。
下一篇:Java上传下载功能的实现
最新资讯
热门推荐