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1.用一条语句得出某日期所在月份的最大天数？
select day(dateadd(dd, -day(2004-02-13), dateadd(mm, 1, 2004-02-13))) as day number
2.少记录变成多条记录问题
有表tbl
日期 收入 支出
2004-02-11 00:00:00 60 45
2004-03-01 00:00:00 60 45
2004-03-02 00:00:00 40 50
2004-03-05 00:00:00 50 40
/*
测试数据：
create table tbl([日期] smalldatetime,[收入] int ,[支出] int)
insert into tbl
select 2004-02-11, 60, 45
union select 2004-03-01,60, 45
union select 2004-03-02,40, 50
union select 2004-03-05,50, 40
*/
要得到的结果：
日期 收入 支出 余额
2004-02-01 00:00:00 null null null
2004-02-02 00:00:00 null null null
2004-02-03 00:00:00 null null null
2004-02-04 00:00:00 null null null
2004-02-05 00:00:00 null null null
2004-02-06 00:00:00 null null null
2004-02-07 00:00:00 null null null
2004-02-08 00:00:00 null null null
2004-02-09 00:00:00 null null null
2004-02-10 00:00:00 null null null
2004-02-11 00:00:00 60 45 15
2004-02-12 00:00:00 null null 15
2004-02-13 00:00:00 null null 15
2004-02-14 00:00:00 null null 15
2004-02-15 00:00:00 null null 15
2004-02-16 00:00:00 null null 15
2004-02-17 00:00:00 null null 15
2004-02-18 00:00:00 null null 15
2004-02-19 00:00:00 null null 15
2004-02-20 00:00:00 null null 15
2004-02-21 00:00:00 null null 15
2004-02-22 00:00:00 null null 15
2004-02-23 00:00:00 null null 15
2004-02-24 00:00:00 null null 15
2004-02-25 00:00:00 null null 15
2004-02-26 00:00:00 null null 15
2004-02-27 00:00:00 null null 15
2004-02-28 00:00:00 null null 15
2004-02-29 00:00:00 null null 15
2004-03-01 00:00:00 60 45 30
2004-03-02 00:00:00 40 50 20
2004-03-03 00:00:00 null null 20
2004-03-04 00:00:00 null null 20
2004-03-05 00:00:00 50 40 30
2004-03-06 00:00:00 null null 30
2004-03-07 00:00:00 null null 30
2004-03-08 00:00:00 null null 30
2004-03-09 00:00:00 null null 30
2004-03-10 00:00:00 null null 30
2004-03-11 00:00:00 null null 30
2004-03-12 00:00:00 null null 30
2004-03-13 00:00:00 null null 30
2004-03-14 00:00:00 null null 30
2004-03-15 00:00:00 null null 30
2004-03-16 00:00:00 null null 30
2004-03-17 00:00:00 null null 30
2004-03-18 00:00:00 null null 30
2004-03-19 00:00:00 null null 30
2004-03-20 00:00:00 null null 30
2004-03-21 00:00:00 null null 30
2004-03-22 00:00:00 null null 30
2004-03-23 00:00:00 null null 30
2004-03-24 00:00:00 null null 30
2004-03-25 00:00:00 null null 30
2004-03-26 00:00:00 null null 30
2004-03-27 00:00:00 null null 30
2004-03-28 00:00:00 null null 30
2004-03-29 00:00:00 null null 30
2004-03-30 00:00:00 null null 30
2004-03-31 00:00:00 null null 30
答案：
select y.[日期], tbl.[收入], tbl.[支出], (
select sum(isnull(tbl.[收入], 0)-isnull(tbl.[支出], 0)) from tbl where [日期]<=y.[日期]) as [余额]
from tbl right join (
select dateadd(dd, n.i, dateadd(dd, 1-day(m.minday), m.minday)) as [日期]
from (
select 0 as i
union all select 1
union all select 2
union all select 3
union all select 4
union all select 5
union all select 6
union all select 7
union all select 8
union all select 9
union all select 10
union all select 11
union all select 12
union all select 13
union all select 14
union all select 15
union all select 16
union all select 17
union all select 18
union all select 19
union all select 20
union all select 21
union all select 22
union all select 23
union all select 24
union all select 25
union all select 26
union all select 27
union all select 28
union all select 29
union all select 30
union all select 31
) n,
(
select min(日期) as minday
from tbl
group by datediff(month, 0, 日期)
) m
where datediff(mm, dateadd(dd, n.i, dateadd(dd, 1-day(m.minday), m.minday)), m.minday)=0) as y
on tbl.[日期]=y.日期
