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无规律自定义分段的分类汇总+交叉表处理-数据库专栏,SQL Server

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/*–原帖地址:http://community.csdn.net/expert/topic/3845/3845290.xml?temp=.3689386–*/

–测试数据create table tb(编号 int,性质 varchar(10),数量 int,指标1 decimal(10,1),指标2 decimal)insert tb select 1 ,00 ,10,1.1 ,10union all select 2 ,01 ,20,1.2 ,20union all select 3 ,00 ,30,1.5 ,10union all select 4 ,01 ,40,1.9 ,35union all select 5 ,00 ,40,1.2 ,20

/*–处理要求

要求得到下述结果:

a                      范围               性质(00)         性质(01)         —————– —————- ————– ————– 指标1               <1.0              .00            .00                         1.0-1.29        .63            .63                         1.3-1.59        .38            .38                         1.9-1.99        .00            .00                          >=2               .00            .00指标1平均值                        1.27           1.55指标2               <10              .00             .00                         10-31            1.00           1.00                         31-50            .00            .00                         >=50             .00            .00指标2平均值                        13.33          27.50数量合计:                          80.00          60.00——————————————————————

分类说明:

                    范围            性质(00)                               性质(01)指标1         <1.0            0                                                    0                               1.0-1.29      (10+40)/(10+30+40)                 20/(20+40)                   1.3-1.59      30/(10+30+40)                            0                   1.6-1.99      0                                                    40/(20+40)                   >=2              0                                                    0指标1平均值:              (1.1+1.5+1.2)/3                          (1.2+1.9)/2

指标2        <10              0                                                     0                  10-30            (10+30+40)/(10+30+40)          20/(20+40)                   31-50            0                                                    40/(20+40)                   >=50            0                                                    0指标2平均值:                  (10+10+20)/3                        (20+35)/2

数量合计:                     10+30+40                                  20+40–*/go

–查询处理select a,范围,[性质(00)],[性质(01)]from(select  a=case a.id when 1 then 指标1 when 21 then 指标2 else end, 范围=a.lb, [性质(00)]=cast(case when b.a>0 then isnull(a.a*1./b.a,0) else 0 end as decimal(10,2)), [性质(01)]=cast(case when b.a>0 then isnull(a.a*1./b.a,0) else 0 end as decimal(10,2)), a.idfrom( select b.id,b.lb,  a=sum(case a.性质 when 00 then a.数量 end),  b=sum(case a.性质 when 01 then a.数量 end) from tb a   right join(   select id=1,lb=<1.0    ,a=null,b=1.0  union all   select id=2,lb=1.0-1.29,a=1.0 ,b=1.3  union all   select id=3,lb=1.3-1.59,a=1.3 ,b=1.9  union all   select id=4,lb=1.9-1.99,a=1.9 ,b=2.0  union all   select id=5,lb=>=2     ,a=2.0 ,b=null  )b on a.指标1>=isnull(b.a,a.指标1)   and a.指标1<isnull(b.b,a.指标1-1) group by b.id,b.lb union all select b.id,b.lb,  a=sum(case a.性质 when 00 then a.数量 end),  b=sum(case a.性质 when 01 then a.数量 end) from tb a right join(  select id=21,lb=<10  ,a=null,b=10  union all  select id=22,lb=10-31,a=10  ,b=31  union all  select id=23,lb=31-50,a=31  ,b=51  union all  select id=25,lb=>=50 ,a=50  ,b=null )b on a.指标2>=isnull(b.a,a.指标2)  and a.指标2<isnull(b.b,a.指标2-1) group by b.id,b.lb)a,( select   a=isnull(sum(case 性质 when 00 then 数量 end),0),  b=isnull(sum(case 性质 when 01 then 数量 end),0) from tb)bunion allselect 指标1平均值,, cast(isnull(  case    when count(case 性质 when 00 then 性质 end)>0   then sum(case 性质 when 00 then 指标1 end)    *1./count(case 性质 when 00 then 性质 end)   else 0   end,0) as decimal(10,2)), cast(isnull(  case    when count(case 性质 when 01 then 性质 end)>0   then sum(case 性质 when 01 then 指标1 end)    *1./count(case 性质 when 01 then 性质 end)   else 0   end,0) as decimal(10,2)), id=6from tbunion allselect 指标2平均值,, cast(isnull(  case    when count(case 性质 when 00 then 性质 end)>0   then sum(case 性质 when 00 then 指标2 end)    *1./count(case 性质 when 00 then 性质 end)   else 0   end,0) as decimal(10,2)), cast(isnull(  case    when count(case 性质 when 01 then 性质 end)>0   then sum(case 性质 when 01 then 指标2 end)    *1./count(case 性质 when 01 then 性质 end)   else 0   end,0) as decimal(10,2)), id=26from tbunion allselect 数量合计:,, isnull(sum(case 性质 when 00 then 数量 end),0), isnull(sum(case 性质 when 01 then 数量 end),0), id=30from tb)a order by idgo

–删除测试drop table tb

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